DAF worked sizing examples

Four complete calculations, from raw production figures to expected effluent quality. These are anonymised composites of real projects, not client case studies — the numbers are representative and the method is exactly the one we use.

The method, in five steps

1. Establish balanced design flow (m³/h) and peak. 2. Calculate solids load = flow × TSS, plus chemical floc from the coagulant dose. 3. Flotation area = design flow ÷ surface loading rate. 4. Air demand = solids load × A/S ratio. 5. Recycle flow = air demand ÷ available dissolved air at working pressure and actual temperature. Step five is where most designs go wrong, because the temperature correction is skipped.

Example 1: brewery, 500,000 hL/year

StepCalculationResult
Production500,000 hL/yr over 330 days1,515 hL/day = 152 m³ beer/day
Effluent volume4.5 L effluent per L beer684 m³/day
Design flowBalanced over 22 h31 m³/h, peak 48 m³/h
InfluentTSS 500 mg/L, COD 2,800 mg/L, filtered COD 2,100 mg/L75 % soluble COD
Solids load31 × 0.50015.5 kg/h
Chemical flocPAC 120 mg/L → ~0.35 kg floc/kg PAC+1.3 kg/h
Flotation area31 ÷ 8 m/h3.9 m² → select 4.5 m²
Air demand16.8 × A/S 0.020.34 kg/h
Available air5 bar, 28 °C, 80 % efficient0.086 kg/m³
Recycle flow0.34 ÷ 0.0864.0 m³/h (13 %)
Expected effluentTSS 25–60 mg/L, COD 1,900–2,300 mg/L
The decisive figure is the 75 % soluble COD. Flotation takes total COD from 2,800 to about 2,100 mg/L — a 25 % reduction. If the consent is 1,000 mg/L COD, the DAF cannot deliver it and anaerobic or aerobic treatment is mandatory. The DAF still earns its place by protecting that biology and cutting its solids load by 90 %.

Example 2: abattoir, 150 cattle/day

StepCalculationResult
Throughput150 cattle/day, 1,200 L effluent per head180 m³/day
Design flowSlaughter 8 h, balanced over 16 h11.3 m³/h, peak 24 m³/h
Influent (blood segregated)TSS 1,800 mg/L, FOG 900 mg/L, COD 4,500 mg/L
Solids load11.3 × (1.800 + 0.900)30.5 kg/h
Chemical flocFeCl₃ 300 mg/L+2.4 kg/h
Flotation area11.3 ÷ 6 m/h1.9 m² → select 2.2 m²
Air demand32.9 × A/S 0.041.32 kg/h
Available air5.5 bar, 30 °C, 80 % efficient0.097 kg/m³
Recycle flow1.32 ÷ 0.09713.6 m³/h (120 %)
Float sludge~33 kg/h dry at 5 %0.66 m³/h, 10.6 m³/day
Expected effluentTSS 60–180 mg/L, FOG 10–30 mg/L, COD 1,600–2,700 mg/L
The 120 % recycle ratio is not an error. High FOG demands a high air-to-solids ratio, and air demand drives recycle flow directly. A supplier quoting 20 % recycle on this duty has sized the unit on a municipal assumption and it will produce a thin float from day one. Note also that blood must be segregated and rendered separately: unsegregated blood roughly triples the COD load and no DAF will compensate.

Example 3: edible oil refinery, 40 t/day

StepCalculationResult
Throughput40 t/day crude, 1.8 m³ effluent per tonne72 m³/day
Design flowBalanced over 20 h3.6 m³/h, peak 6 m³/h
Influent after interceptionFOG 1,100 mg/L, TSS 700 mg/L, COD 6,000 mg/L
Solids load3.6 × (1.100 + 0.700)6.5 kg/h
Chemical flocPAC 350 mg/L+0.44 kg/h
Flotation area3.6 ÷ 5.5 m/h0.65 m² → select 0.8 m²
Air demand6.9 × A/S 0.0550.38 kg/h
Available air5.5 bar, 35 °C, 80 % efficient0.090 kg/m³
Recycle flow0.38 ÷ 0.0904.2 m³/h (117 %)
Oil recovered~6.5 kg/h float, 25 % oil, 300 days~11.7 t/year acid oil
Expected effluentFOG 20–60 mg/L, TSS 50–100 mg/L, COD 2,000–3,500 mg/L
Small flow, high concentration, high recycle. The recovered oil is worth having: at 11.7 t/year and typical biodiesel feedstock pricing, it substantially offsets the chemical and power bill for the whole effluent plant.

Example 4: municipal works, 12,000 m³/day

StepCalculationResult
Average flow12,000 m³/day500 m³/h
Design flowPeak factor 1.8900 m³/h
InfluentTSS 320 mg/L, BOD 280 mg/L, TP 8 mg/L
Solids load at peak900 × 0.320288 kg/h
Chemical flocFeCl₃ 70 mg/L+30 kg/h
Flotation area900 ÷ 22 m/h high-rate41 m² → 2 cells × 21 m²
Air demand318 × A/S 0.0123.8 kg/h
Available air5 bar, 25 °C, 80 % efficient0.103 kg/m³
Recycle flow3.8 ÷ 0.10337 m³/h (4 %)
Sludge~250 kg/h dry at 4 %6.3 m³/h
Expected effluentTSS 40–65 mg/L, BOD 120–150 mg/L, TP <2 mg/L
The 4 % recycle ratio at the municipal end of the range is the mirror image of the abattoir’s 120 %. Both are correct for their stream, which is precisely why recycle ratio must be calculated rather than assumed.

What these four show

BreweryAbattoirEdible oilMunicipal
Design flow31 m³/h11.3 m³/h3.6 m³/h900 m³/h
Surface loading8 m/h6 m/h5.5 m/h22 m/h
A/S ratio0.0200.0400.0550.012
Recycle ratio13 %120 %117 %4 %
COD removal25 %50 %55 %50 %
DAF alone meets consent?NoUsually notNoAs primary stage, yes
Recycle ratio spans thirty-fold across these four cases. Any rule of thumb that quotes a single figure is wrong for at least three of them.

Run your own case in the DAF sizing calculator, or read the underlying equations in the design parameters reference.